




from __future__ import annotations

from collections.abc import Generator

import requests
from bsa import BeautifulSoup

__a          =			"https://www.indeed.co.in/jobs?q=mobile+app+development&l="







def lowerCamelCase__       (      _lowercase = "mumbai"				):

     '''simple docstring'''


     UpperCAmelCase_      :							str       =      BeautifulSoup(requests.get(url + location				).content			,						'''html.parser'''				)
     # This attribute finds out all the specifics listed in a job
     for job in soup.find_all('''div'''			,						attrs={'''data-tn-component''': '''organicJob'''}				):
          UpperCAmelCase_      :							Tuple       =      job.find('''a'''			,						attrs={'''data-tn-element''': '''jobTitle'''}				).text.strip()
          UpperCAmelCase_      :							Dict       =      job.find('''span'''			,						{'''class''': '''company'''}				).text.strip()
          yield job_title, company_name


if __name__ == "__main__":
     for i, job in enumerate(fetch_jobs('Bangalore'), 1):
          print(F"""Job {i:>2} is {job[0]} at {job[1]}""")





from collections import defaultdict







def lowerCamelCase__       (      _lowercase			,						_lowercase				):

     '''simple docstring'''


     UpperCAmelCase_      :							Optional[int]       =      first_str.lower().strip()
     UpperCAmelCase_      :							Any       =      second_str.lower().strip()

     # Remove whitespace
     UpperCAmelCase_      :							Any       =      first_str.replace(''' '''			,						''''''				)
     UpperCAmelCase_      :							int       =      second_str.replace(''' '''			,						''''''				)

     # Strings of different lengths are not anagrams
     if len(_lowercase				) != len(_lowercase				):
          return False

     # Default values for count should be 0
     UpperCAmelCase_      :							defaultdict[str, int]       =      defaultdict(_lowercase				)

     # For each character in input strings,
     # increment count in the corresponding
     for i in range(len(_lowercase				)				):
          count[first_str[i]] += 1
          count[second_str[i]] -= 1

     return all(_count == 0 for _count in count.values()				)


if __name__ == "__main__":
     from doctest import testmod

     testmod()
     __a          =			input('Enter the first string ').strip()
     __a          =			input('Enter the second string ').strip()

     __a          =			check_anagrams(input_a, input_b)
     print(F"""{input_a} and {input_b} are {"" if status else "not "}anagrams.""")