



import random
from typing import Any




def 						SCREAMING_SNAKE_CASE__ (   lowercase					)  ->       list[Any]:
   for _ in range(len(_UpperCamelCase					)					):
      snake_case				:    Dict           =	random.randint(0						,len(_UpperCamelCase					) - 1					)
      snake_case				:    List[str]           =	random.randint(0						,len(_UpperCamelCase					) - 1					)
      snake_case     , snake_case				:    Tuple           =	data[b], data[a]
   return data


if __name__ == "__main__":
       lowerCamelCase	:	List[Any]				=   [0, 1, 2, 3, 4, 5, 6, 7]
       lowerCamelCase	:	Optional[int]				=   ['python', 'says', 'hello', '!']
       print('Fisher-Yates Shuffle:')
       print('List', integers, strings)
       print('FY Shuffle', fisher_yates_shuffle(integers), fisher_yates_shuffle(strings))











from math import pow




def 						SCREAMING_SNAKE_CASE__ (   lowercase						,lowercase						,lowercase						,lowercase						,lowercase						,)  ->       tuple[int, int]:
   if current_sum == needed_sum:
      # If the sum of the powers is equal to needed_sum, then we have a solution.
      solutions_count += 1
      return current_sum, solutions_count

   snake_case				:    Union[str, Any]           =	int(pow(lowercase						,lowercase					)					)
   if current_sum + i_to_n <= needed_sum:
      # If the sum of the powers is less than needed_sum, then continue adding powers.
      current_sum += i_to_n
      snake_case     , snake_case				:    List[Any]           =	backtrack(
          lowercase						,lowercase						,current_number + 1						,lowercase						,lowercase					)
      current_sum -= i_to_n
   if i_to_n < needed_sum:
      # If the power of i is less than needed_sum, then try with the next power.
      snake_case     , snake_case				:    str           =	backtrack(
          lowercase						,lowercase						,current_number + 1						,lowercase						,lowercase					)
   return current_sum, solutions_count




def 						SCREAMING_SNAKE_CASE__ (   lowercase						,lowercase					)  ->       int:
   if not (1 <= needed_sum <= 1000 and 2 <= power <= 10):
      raise ValueError(
          """Invalid input\n"""
          """needed_sum must be between 1 and 1000, power between 2 and 10."""					)

   return backtrack(lowercase						,lowercase						,1						,0						,0					)[1]  # Return the solutions_count


if __name__ == "__main__":
       import doctest

       doctest.testmod()





