A common compound $\bf{A}$ is composed of four elements and has a boiling point of $\rm{189\degree C}$, with one element accounting for $\rm{41.04\%}$ of its composition. Compound $\bf{B}$ has an empirical formula molecular weight of 63.46. At $\rm{195 ~K}$, $\bf{A}$ and $\bf{B}$ are mixed and added to ethanol, followed by the addition of a weak base $\bf{C}$ after a while, resulting in the formation of a pungent-smelling liquid $\bf{D}$ and a volatile, foul-smelling liquid $\bf{E}$.

It is known that the mass fraction of a certain element in $\bf{C}$ is $13.86\%$.

Which of the following statements is correct:
某常见化合物$\bf{A}$由四种元素组成,沸点为$\rm{189\degree C}$,其中一种元素含量为$\rm{41.04\%}$。化合物$\bf{B}$最简式的分子量为63.46,在$\rm{195 ~K}$下,将$\bf{A}$与$\bf{B}$混合加入到乙醇中,过一会儿再加入弱碱$\bf{C}$,生成了一种刺激性气味液体$\bf{D}$,和一种挥发性臭味的液体$\bf{E}$。

已知$\bf{C}$中某种元素的质量分数为$13.86\%$。

下列说法正确的是：
All other options are incorrect
The chemical equation for the question involves, when balanced with the simplest integer ratio of coefficients, a sum of coefficients for all species less than 10.
The chemical equation for the reaction involved in the problem, when balanced with the simplest integer ratio of coefficients, has an even sum of coefficients for all species.
The chemical equation for the reaction involved in the problem, when balanced with the smallest possible integer ratio for the coefficients, has a sum of all species' coefficients that is a prime number.
The reaction chemical equations involved in the question, after balancing with the simplest integer ratio for coefficients, have a sum of coefficients for all species that is a multiple of 3.
The reaction chemical equation involved in the question, after balancing with the simplest integer ratio of coefficients, has a sum of coefficients for all species equal to 10.
The reaction chemical equation involved in the problem, after being balanced with the simplest integer ratio as the coefficient sum, has a coefficient sum of 13 for all species.
The problem involves the reaction chemical equation, and the products have 4 kinds of gases at $\rm{300 ~K}$.
Cannot use $\rm{(COCF_3)_2O}$ to replace $\bf{B}$ to undergo a similar reaction.
Cannot use $\rm{DCC}$ (dicyclohexylcarbodiimide) to replace $\bf{B}$ to undergo a similar reaction to obtain $\bf{D}$.
其他选项均不正确
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和小于10
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和为偶数
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和为质数
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和为3的倍数
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和为10
题目涉及的反应化学方程式，以系数和为最简整数比配平后，所有物种的系数和为13
题目涉及的反应化学方程式，产物在$\rm{300 ~K}$下有4种气体
不能采用$\rm{(COCF_3)_2O}$代替$\bf{B}$发生类似反应
不能采用$\rm{DCC}$（二环己基碳二亚胺）代替$\bf{B}$发生类似反应得到$\bf{D}$
$\bf{B}$'s simplest formula has a molecular weight of 63.46 and can only contain $\rm{Cl}$ with a atomic weight of 35.45.

<Checkpoint>[$\bf{B}$ can only contain $\rm{Cl}$ with a molecular weight of 35.45](1)</Checkpoint>

The remaining molecular weight is 28.01, which is obviously $\rm{CO}$; ($\rm{N_2}$ is 28.02, which does not match). Therefore, the simplest formula of $\bf{B}$ is $\rm{COCl}$, and the actual one should be oxalyl chloride $\rm{(COCl)_2}$.

<Checkpoint>[The simplest formula of $\bf{B}$ is $\rm{COCl}$, and the actual one should be oxalyl chloride $\rm{(COCl)_2}$](1)</Checkpoint>

$\bf{E}$ has a volatile odor, considering that $\bf{E}$ contains sulfur element; then $\bf{A}$ contains sulfur element. Considering that $\bf{A}$ is composed of four elements and is common, consider common short-period elements such as $\rm{C,H,O,Cl}$.

<Checkpoint>[$\bf{E}$ has a volatile odor, considering that $\bf{E}$ contains sulfur element; then $\bf{A}$ contains sulfur element](1)</Checkpoint>

Common four-element compounds containing sulfur are likely to be organic compounds; consider common ethanethiol $\rm{CH_3CH_2SH}$ and dimethyl sulfoxide $\rm{(CH_3)_2SO}$. According to the mass fraction, $\bf{A}$ is $\rm{(CH_3)_2SO}$, in which the mass fraction of sulfur is $\rm{41.04\%}$.

<Checkpoint>[$\bf{A}$ is $\rm{(CH_3)_2SO}$](2)</Checkpoint>

Then, at this time, $\bf{E}$ is a volatile odorous liquid, then $\bf{E}$ is dimethyl sulfide $\rm{(CH_3)_2S}$; considering the reaction temperature and reactants (ethanol, oxalyl chloride, dimethyl sulfoxide, producing dimethyl sulfide), it can be judged that the reaction is the Swern oxidation reaction. Therefore, the irritating odorous liquid $\bf{D}$ produced is acetaldehyde $\rm{CH_3CHO}$.

<Checkpoint>[$\bf{E}$ is dimethyl sulfide $\rm{(CH_3)_2S}$](1)</Checkpoint>

<Checkpoint>[This reaction is the Swern oxidation reaction](2)</Checkpoint>

<Checkpoint>[$\bf{D}$ is acetaldehyde $\rm{CH_3CHO}$](1)</Checkpoint>

In Swern oxidation, oxalyl chloride is converted into $\rm{CO,CO_2,HCl}$, which requires the participation of a weak base to neutralize the generated $HCl$. The commonly used weak base is triethylamine $\rm{N(C_2H_5)_3}$. According to the mass fraction, the weak base $\bf{C}$ is indeed triethylamine $\rm{N(C_2H_5)_3}$.

<Checkpoint>[In Swern oxidation, oxalyl chloride is converted into $\rm{CO,CO_2,HCl}$](1)</Checkpoint>

<Checkpoint>[$\bf{C}$ is triethylamine $\rm{N(C_2H_5)_3}$](1)</Checkpoint>

Therefore, write the reaction equation:

$\rm{C_2H_5OH + (CH_3)_2SO + (COCl)_2 + 2N(C_2H_5)_3 = 2N(C_2H_5)_3\cdot HCl + CO_2 + CO + CH_3CHO + (CH_3)_2S}$

<Checkpoint>[$\rm{C_2H_5OH + (CH_3)_2SO + (COCl)_2 + 2N(C_2H_5)_3 = 2N(C_2H_5)_3\cdot HCl + CO_2 + CO + CH_3CHO + (CH_3)_2S}$](2)</Checkpoint>

The sum of the reaction coefficients is 11, only option D is correct.

At $\rm{300 ~K}$, acetaldehyde is a gas and dimethyl sulfide is a liquid, so there are only three gases, option H is wrong.

<Checkpoint>[At $\rm{300 ~K}$, acetaldehyde is a gas and dimethyl sulfide is a liquid](1)</Checkpoint>

In Swern oxidation, $\rm{(COCF_3)_2}$ or $\rm{DCC}$ can be used to replace oxalyl chloride, options I and J are wrong.

<Checkpoint>[In Swern oxidation, $\rm{(COCF_3)_2O}$ or $\rm{DCC}$ can be used to replace oxalyl chloride](1)</Checkpoint>
$\bf{B}$最简式的分子量为63.46,只能含有分子量为35.45的$\rm{Cl}$。

<Checkpoint>[$\bf{B}$只能含有原子量为35.45的$\rm{Cl}$](1)</Checkpoint>

剩余分子量为28.01，很明显为$\rm{CO}$；（$\rm{N_2}$为28.02，不符合）因此$\bf{B}$最简式为$\rm{COCl}$，实际应为草酰氯$\rm{(COCl)_2}$。

<Checkpoint>[$\bf{B}$最简式为$\rm{COCl}$，实际应为草酰氯$\rm{(COCl)_2}$](1)</Checkpoint>

$\bf{E}$有挥发性臭味，考虑$\bf{E}$含硫元素；则$\bf{A}$含有硫元素。考虑$\bf{A}$由四种元素组成且常见，因此考虑常见元素$\rm{C,H,O,Cl}$等短周期元素。

<Checkpoint>[$\bf{E}$有挥发性臭味，考虑$\bf{E}$含硫元素；则$\bf{A}$含有硫元素](1)</Checkpoint>

含硫的常见四种元素化合物很可能为有机物；考虑常见的乙硫醇$\rm{CH_3CH_2SH}$和二甲亚砜$\rm{(CH_3)_2SO}$，根据质量分数可知$\bf{A}$为$\rm{(CH_3)_2SO}$，其中硫质量分数为$\rm{41.04\%}$。

<Checkpoint>[$\bf{A}$为$\rm{(CH_3)_2SO}$](2)</Checkpoint>

那么此时$\bf{E}$是挥发性臭味的液体，则$\bf{E}$为二甲硫醚$\rm{(CH_3)_2S}$；考虑反应温度和反应物（乙醇，草酰氯，二甲亚砜，生成二甲硫醚），可判断该反应为Swern氧化反应。故生成的刺激性气味液体$\bf{D}$为乙醛$\rm{CH_3CHO}$。

<Checkpoint>[$\bf{E}$为二甲硫醚$\rm{(CH_3)_2S}$](1)</Checkpoint>

<Checkpoint>[该反应为Swern氧化反应](2)</Checkpoint>

<Checkpoint>[$\bf{D}$为乙醛$\rm{CH_3CHO}$](1)</Checkpoint>

Swern氧化中草酰氯转化为$\rm{CO,CO_2,HCl}$，需要弱碱的参与以中和产生的$HCl$，常用的弱碱为三乙胺$\rm{N(C_2H_5)_3}$，根据质量分数可知弱碱$\bf{C}$确实为三乙胺$\rm{N(C_2H_5)_3}$。

<Checkpoint>[Swern氧化中草酰氯转化为$\rm{CO,CO_2,HCl}$](1)</Checkpoint>

<Checkpoint>[$\bf{C}$为三乙胺$\rm{N(C_2H_5)_3}$](1)</Checkpoint>

因此写出反应方程式：

$\rm{C_2H_5OH + (CH_3)_2SO + (COCl)_2 + 2N(C_2H_5)_3 = 2N(C_2H_5)_3\cdot HCl + CO_2 + CO + CH_3CHO + (CH_3)_2S}$

<Checkpoint>[$\rm{C_2H_5OH + (CH_3)_2SO + (COCl)_2 + 2N(C_2H_5)_3 = 2N(C_2H_5)_3\cdot HCl + CO_2 + CO + CH_3CHO + (CH_3)_2S}$](2)</Checkpoint>

反应系数和为11，只有选项D正确。

$\rm{300 ~K}$下乙醛为气体，二甲硫醚为液体，因此只有三种气体，选项H错误。

<Checkpoint>[$\rm{300 ~K}$下乙醛为气体，二甲硫醚为液体](1)</Checkpoint>

Swern氧化可以使用$\rm{(COCF_3)_2}$或者$\rm{DCC}$代替草酰氯，选项I,J错误。

<Checkpoint>[Swern氧化可以使用$\rm{(COCF_3)_2O}$或者$\rm{DCC}$代替草酰氯](1)</Checkpoint>