<MultiModal>![CC(C)(C)OCC1=CC=CC=C1.CC(C)([N+]#[C-])C>[DDQ],[AgOTf],[PhCl],[$N_2$]>[A], A is the reaction product, the reaction temperature is $80\degree\mathrm{C}$](/media/uploads/7e581c09-dbd9-42e1-9595-d920f8dda7f7.png)</MultiModal>

Where the amount of $\mathrm{DDQ}$ and tert-butyl isocyanide is at least twice the amount of benzyl tert-butyl ether. Mechanistic studies show that the reaction is not a free radical reaction mechanism. Deduce the structural formula of the reaction product $\mathbf{A}$ (without considering stereoisomers).
<MultiModal>![CC(C)(C)OCC1=CC=CC=C1.CC(C)([N+]#[C-])C>[DDQ],[AgOTf],[PhCl],[$N_2$]>[A],A为反应产物,反应温度为$80\degree\mathrm{C}$](/media/uploads/7e581c09-dbd9-42e1-9595-d920f8dda7f7.png)</MultiModal>

其中$\mathrm{DDQ}$和叔丁基异氰的量至少是苄基叔丁基醚的两倍，机理研究表明该反应并非自由基反应机理，试推断出反应产物$\mathbf{A}$的结构式（不考虑立体异构）
All other options are incorrect
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其他选项均不正确
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First, the benzyl ether substrate is oxidized by $\mathrm{DDQ}$ to form intermediate 1

<MultiModal>![CC(C)(C)/[O+]=C/C1=CC=CC=C1](/media/uploads/095a5aeb-a7e5-424c-8c8d-cda025f25b24.png)</MultiModal>

<Checkpoint>[CC(C)(C)/[O+]=C/C1=CC=CC=C1](1)</Checkpoint>

Subsequently, a one-step addition reaction occurs to obtain intermediate 2

<MultiModal>![CC(C)(C)OC(C#[N+]C(C)(C)C)C1=CC=CC=C1](/media/uploads/7f8a939c-cf12-4f34-ad47-6544fc0cb7a3.png)</MultiModal>

<Checkpoint>[CC(C)(C)OC(C#[N+]C(C)(C)C)C1=CC=CC=C1](1)</Checkpoint>

A molecule of addition reaction occurs again to obtain intermediate 3

<MultiModal>![CC(OC(/C(C#[N+]C(C)(C)C)=N/C(C)(C)C)C1=CC=CC=C1)(C)C](/media/uploads/fbb6c3a2-0f29-4407-8c90-6068c078b7d7.png)</MultiModal>

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Subsequently, a tert-butyl carbenium ion is eliminated to obtain intermediate 4

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Finally, it is oxidized again by a molecule of $\mathrm{DDQ}$ to obtain the reaction product $\mathbf{A}$

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首先苄醚底物被$\mathrm{DDQ}$氧化形成中间体1

<MultiModal>![CC(C)(C)/[O+]=C/C1=CC=CC=C1](/media/uploads/095a5aeb-a7e5-424c-8c8d-cda025f25b24.png)</MultiModal>

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随后发生一步加成反应得到中间体2

<MultiModal>![CC(C)(C)OC(C#[N+]C(C)(C)C)C1=CC=CC=C1](/media/uploads/7f8a939c-cf12-4f34-ad47-6544fc0cb7a3.png)</MultiModal>

<Checkpoint>[CC(C)(C)OC(C#[N+]C(C)(C)C)C1=CC=CC=C1](1)</Checkpoint>

再次发生一分子加成反应得到中间体3

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随后脱去叔丁基正离子得到中间体4

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最后再被一分子$\mathrm{DDQ}$氧化得到反应产物$\mathbf{A}$

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