The following are two repeating units of the random copolymer $\bf A$:
<MultiModal>![O=C(NCCOCCOCCOCCOCCN1)C(C[*])CC([*])C1=O and CCCCNC(C([*])C[*])=O, where "*" indicates other atoms connected to the repeating unit](/media/uploads/1bf08571-88ab-4c5a-99eb-35191a218b48.png)</MultiModal>

1,2-Dichloroethane was used as a solvent during the preparation of $\bf A$, $\rm Fe_2(C_5H_5)_2(CO)_4$ and ethyl 2-iodoisobutyrate were used as initiators, and an appropriate amount of iodine $\rm I_2$ was added to the system. The reaction initiation process produced a mononuclear complex $\bf B$ of $\rm Fe(II)$.

Which of the following statements is correct:
1. $\rm Fe$ in $\bf B$ satisfies the 18-electron rule
2. This reaction is coordination polymerization
3. It is known that a larger number-average molecular weight can be obtained when this polymerization reaction is carried out in cyclohexane, which is mainly related to intermolecular hydrogen bonds.
4. $\bf A$ can form a spherical structure in water. If the main chain of $\bf A$ is represented by a black curve, one type of side chain is represented by an orange curve connected to the main chain at one end, and the other type of side chain is represented by a blue line connected to the main chain at both ends (i.e., forming a ring), and the connection point between the side chain and the main chain is represented by a red dot, then $\bf A$ can be represented as: <MultiModal>![The background of this image is pure white and does not contain any text, coordinate axes, or legends. A black, irregular closed curve encloses a hollow area. Multiple red dots are evenly distributed on the black curve, serving as connection points between different colored curves. Within the space enclosed by the black curve, multiple blue curves are filled, with both ends of these blue curves connected to the black curve, forming a ring and intertwining and overlapping each other. The entire outer circumference of the black curve is connected to multiple orange curves, extending outward in a radial pattern.](/media/uploads/484396a7-1638-400d-b92a-da282b26e166.png)</MultiModal>
5.  $\bf A$ can also form a spherical structure in chloroform. With reference to the above representation method, it can be represented as: <MultiModal>![The background of this image is pure white and does not contain any text, coordinate axes, or legends. A black, irregular closed curve encloses a hollow area. Multiple red dots are evenly distributed on the black curve, serving as connection points between different colored curves. Outside the black curve, there are multiple blue curves, with both ends of these blue curves connected to the black curve to form a ring, and these rings surround the black curve. The entire inner circumference of the black curve is connected to multiple orange curves, extending inward in a radial pattern.](/media/uploads/755e988d-8ae9-47bd-ab85-5e9e19ba923b.png)</MultiModal>
6. $\bf A$ has a lamellar microphase separated structure in the solid state. With reference to the above representation method, it can be represented as: <MultiModal>![The image is a structural diagram presented on a white background, which does not contain any text, numbers, or labels. A black straight line extends horizontally, with blue lines on one side. Both ends of the blue lines are connected to the black straight line to form a ring, and these rings are evenly distributed; on the other side, there are orange lines, with one end of the orange lines connected to the black straight line, arranged at equal intervals. Such a set of lines is called X. If the blue lines are facing upwards and the orange lines are facing downwards, it is X+; otherwise, it is X-. There are now 3 X+ and 3 X- arranged alternately and closely in the vertical direction. The blue lines on different X are staggered and close to each other one by one, and the orange lines on different X are also staggered and close to each other one by one.](/media/uploads/5598fbc4-c82e-4fd9-af13-bc308df70aaa.png)</MultiModal> (Note: Red dots are not described in the picture, but do not judge the statement to be wrong because of this)
以下是无规共聚物$\bf A$的两种重复单元：
<MultiModal>![O=C(NCCOCCOCCOCCOCCN1)C(C[*])CC([*])C1=O和CCCCNC(C([*])C[*])=O，这里标注“*”的为重复单元连接的其他原子](/media/uploads/1bf08571-88ab-4c5a-99eb-35191a218b48.png)</MultiModal>

制备$\bf A$时使用了1,2-二氯乙烷为溶剂，$\rm Fe_2(C_5H_5)_2(CO)_4$和2-碘代异丁酸乙酯作为引发剂，并向体系中加入了适量的碘$\rm I_2$ 。反应引发过程产生了$\rm Fe(II)$的单核配合物$\bf B$。

下列说法正确的是：
1. $\bf B$中$\rm Fe$满足18电子规则
2. 该反应为配位聚合
3. 已知该聚合反应在环己烷中进行时可以获得更大的数均分子量，这主要与分子间氢键有关
4. $\bf A$在水中可以形成球状结构。若将$\bf A$的主链以黑色曲线表示，一种支链用一端连在主链的橙色曲线表示，另一种支链用两端连在主链的蓝色线条表示（即构成了一个环），支链与主链连接处用红色圆点表示，则$\bf A$可以表示为：<MultiModal>![该图像背景为纯白色，不包含任何文字、坐标轴或图例。图中一条黑色的、不规则的闭合曲线围成了一个中空的区域，在黑色曲线的上均匀地分布着多个红色圆点，为不同颜色曲线之间的连接点。在这条黑色曲线所包围的内部空间里，填充着多条蓝色的曲线，这些蓝色曲线的两端都连接在黑色曲线上从而构成一个环，并相互交织、重叠。黑色曲线外侧一整圈都连接着多条橙色曲线，呈辐射状向外延伸。](/media/uploads/484396a7-1638-400d-b92a-da282b26e166.png)</MultiModal>
5.  $\bf A$在氯仿中也可以形成球状结构，参照上面的表示方法，则可以表示为：<MultiModal>![该图像背景为纯白色，不包含任何文字、坐标轴或图例。图中一条黑色的、不规则的闭合曲线围成了一个中空的区域，在黑色曲线的上均匀地分布着多个红色圆点，为不同颜色曲线之间的连接点。在这条黑色曲线的外面有着多条蓝色的曲线，这些蓝色曲线的两端都连接在黑色曲线上从而构成一个环，这些环环绕了黑色曲线一圈。黑色曲线内侧一整圈都连接着多条橙色曲线，呈辐射状向内延伸。](/media/uploads/755e988d-8ae9-47bd-ab85-5e9e19ba923b.png)</MultiModal>
6. $\bf A$在固态具有片层状的微相分离结构，参照上面的表示方法，则可以表示为：<MultiModal>![该图像是一张在白色背景上呈现的结构示意图，其中不包含任何文字、数字或标签。黑色直线水平延伸，其一侧有蓝色线条，蓝色线条的两端连接在黑色直线上从而构成一个环，这些环等距分布；另一侧有橙色线条，橙色线条的一端连接着黑色直线，等距排布。将这样的一组线条称为X，若蓝色线条朝上，橙色线条朝下则为X+；否则为X-。现有3个X+和3个X-在竖直方向上交替紧密排布，不同X上的蓝色线条一个一个交错紧靠，不同X上的橙色线条亦一个一个交错紧靠。](/media/uploads/5598fbc4-c82e-4fd9-af13-bc308df70aaa.png)</MultiModal>（注意：图片中未描述红色圆点，但不要因此就判断该说法错误）
All other options are incorrect
1,3,6
1,3,4,5,6
2,6
4,6
2,3,5
3,5,6
1,4
3,4
6
1,3
2,6
3
5,6
1,3,4,6
1,6
1,4,5,6
3,4,5,6
3,4,6
其他选项均不正确
1,3,6
1,3,4,5,6
2,6
4,6
2,3,5
3,5,6
1,4
3,4
6
1,3
2,6
3
5,6
1,3,4,6
1,6
1,4,5,6
3,4,5,6
3,4,6
The addition of an appropriate amount of iodine can transform active free radicals in the system into "dormant species" and generate iodine radicals, thereby controlling the molecular weight of the polymer and achieving a narrow molecular weight distribution. The initiation step of the reaction is the homolytic cleavage of the $\rm C-I$ bond in ethyl 2-iodoisobutyrate. The iodine radical reacts with $\rm Fe_2(C_5H_5)_2(CO)_4$ to form $\rm Fe(C_5H_5)(CO)_2I$. In this way, the $\rm Fe$ is in the +2 oxidation state, surrounded by $\rm 6+6+2+2+2$, a total of 18 electrons, so statement 1 is correct.

<Checkpoint>[A mononuclear complex of $\rm Fe$, $\rm Fe(C_5H_5)(CO)_2I$, is generated](1)</Checkpoint>

<Checkpoint>[$\rm Fe$ in $\rm Fe(C_5H_5)(CO)_2I$ satisfies the 18-electron rule](0.5)</Checkpoint>

The cleavage of the $\rm C-I$ bond generates the $\rm \alpha-C$ free radical, which initiates polymerization through addition to the double bond, which is free radical polymerization, so statement 2 is incorrect.

<Checkpoint>[This reaction is free radical polymerization](1)</Checkpoint>

The structures of the two monomers used in the reaction are as follows:
<MultiModal>![The SMILES notations of the two monomers are O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C and CCCCNC(C=C)=O](/media/uploads/a7eb13f7-f5f6-44ef-9c4a-9d63789312b1.png)</MultiModal>

O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C can form intramolecular hydrogen bonds $\rm N-H···O=C$ in 1,2-dichloroethane, bringing the two carbon-carbon double bonds closer together. Therefore, these two carbon-carbon double bonds are easily subjected to successive addition and ring closure by free radicals, strung together in one main chain. In cyclohexane, this type of hydrogen bond is not easily formed, and the two carbon-carbon double bonds are far apart, making it more likely to react separately with two different free radicals, thereby forming connections between two different main chains, leading to crosslinking and higher number average molecular weight, i.e., more double bonds participate in chain growth of the polymerization rather than ring closure. So statement 3 is incorrect.

<Checkpoint>[O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C can form intramolecular hydrogen bonds $\rm N-H···O=C$ in 1,2-dichloroethane, bringing the two carbon-carbon double bonds closer together](1)</Checkpoint>

The blue lines represent crown ether fragments, and the orange lines represent butyl groups. The former can form hydrogen bonds with water and is hydrophilic, while the latter is hydrophobic.

<Checkpoint>[The blue lines represent hydrophilic fragments, and the orange lines represent hydrophobic fragments](1)</Checkpoint>

Therefore, the correct representation is: in water, the blue lines face outwards and the orange lines face inwards; in chloroform, the blue lines face inwards and the orange lines face outwards, so statements 4 and 5 are incorrect.

<Checkpoint>[In water, the blue lines face outwards and the orange lines face inwards; in chloroform, the blue lines face inwards and the orange lines face outwards](1)</Checkpoint>

In the layered structure in the solid state, the hydrophilic blue fragments face together, and the hydrophobic orange fragments face together, so statement 6 is correct.

<Checkpoint>[In the layered structure in the solid state, the hydrophilic blue lines face together, and the hydrophobic orange lines face together](1)</Checkpoint>

Therefore, choose P
这里加入适量的碘单质可以将体系中的活性自由基转化为“休眠种”并产生碘自由基，从而控制控制聚合物的分子量并实现窄分子量分布。该反应的引发步骤为2-碘代异丁酸乙酯中的$\rm C-I$键均裂，碘自由基与$\rm Fe_2(C_5H_5)_2(CO)_4$反应形成$\rm Fe(C_5H_5)(CO)_2I$，这样$\rm Fe$为+2价，周围有$\rm 6+6+2+2+2$共18电子，说法1正确

<Checkpoint>[生成了$\rm Fe$的单核配合物$\rm Fe(C_5H_5)(CO)_2I$](1)</Checkpoint>

<Checkpoint>[$\rm Fe(C_5H_5)(CO)_2I$中$\rm Fe$满足18电子规则](0.5)</Checkpoint>

$\rm C-I$键断裂生成了$\rm \alpha-C$自由基，与双键进行加成引发聚合，为自由基聚合，说法2错误

<Checkpoint>[该反应为自由基聚合](1)</Checkpoint>

该反应用的两种单体结构如下：
<MultiModal>![两种单体的SMILES分别为O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C和CCCCNC(C=C)=O](/media/uploads/a7eb13f7-f5f6-44ef-9c4a-9d63789312b1.png)</MultiModal>

O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C在1,2-二氯乙烷中可以形成分子内氢键$\rm N-H···O=C$，拉近两个碳碳双键的距离，因此这两个碳碳双键容易被自由基连续加成关环，串在一根主链中，；在环己烷中不容易形成这种氢键，两个碳碳双键距离远，更可能与两个不同的自由基分别反应，从而在两条不同的主链之间形成连接，导致交联和更高的数均分子量，即更多的双键参与了聚合的链增长而非关环。说法3错误

<Checkpoint>[O=C(NCCOCCOCCOCCOCCOCCNC(C=C)=O)C=C在1,2-二氯乙烷中可以形成分子内氢键$\rm N-H···O=C$，拉近两个碳碳双键的距离](1)</Checkpoint>

蓝色线条代表冠醚片段，橙色线条代表丁基，前者可以与水形成氢键，是亲水的，而后者是疏水的

<Checkpoint>[蓝色线条代表亲水片段，橙色线条代表疏水片段](1)</Checkpoint>

因此正确的画法是：在水中蓝色线条朝外，橙色线条朝内；氯仿中蓝色线条朝内，橙色线条朝外，说法4和5错误

<Checkpoint>[在水中蓝色线条朝外，橙色线条朝内，氯仿中蓝色线条朝内，橙色线条朝外](1)</Checkpoint>

在固态的层状结构中，亲水性的蓝色片段朝着一起，疏水性的橙色片段朝着一起，说法6正确

<Checkpoint>[在固态的层状结构中，亲水性的蓝色线条朝着一起，疏水性的橙色线条朝着一起](1)</Checkpoint>

故选P