A crystalline compound with the chemical formula $\mathbf{AB}$ belongs to the tetragonal crystal system and has a density of $10.27 \mathrm { g } / \mathrm { c m } ^ { 3 }$. Both $\mathbf{A}$ and $\mathbf{B}$ are 4-coordinated, and their coordination configurations are different. There is only one type of $\mathbf{A}-\mathbf{B}$ bond length in the crystal, which is 231.0 $\mathrm{pm}$. The structure can be regarded as an infinite chain structure of $\mathbf{AB}_2$. The chains in the same xy plane are parallel to each other. The chains can be regarded as ribbon-like chains extending in the a or b direction, with a certain width in the c direction. The chains in adjacent xy planes are perpendicular to each other and share vertices. The shortest $\mathbf{A}-\mathbf{A}$ distance is 347.0 $\mathrm{pm}$. There are the following statements:

1. The lattice type of the crystal is $tI$.

2. All $\mathbf{B}$ atoms in the crystal have the same spatial environment.

3. The fourth-period element in the same group as $\mathbf{A}$ exists in nature as a simple substance.

Then, all the correct options are:
化学式为$\mathbf{AB}$的化合物晶体属于四方晶系，密度为 $10.27 \mathrm { g } / \mathrm { c m } ^ { 3 }$ 。其中$\mathbf{A}$与$\mathbf{B}$ 均为4配位且配位构型不相同。晶体中$\mathbf{A}-\mathbf{B}$只有一种键长 231.0 $\mathrm{pm}$。其结构可以视作 $\mathbf{AB}_2$ 的无限链结构，在同一个xy平面中的链互相平行，链可以看作一条在a或者b方向延伸的带状链，在c方向具有一定宽度，相邻的两个xy平面中的链互相垂直且共用顶点。$\mathbf{A}-\mathbf{A}$的最近距离为347.0 $\mathrm{pm}$。有以下的几个说法：

1，该晶体点阵形式为$tI$ 。

2，该晶体中所有$\mathbf{B}$原子的空间环境相同。

3，与$\mathbf{A}$同族的第四周期元素在自然界中存在单质形态。

则其中所有正确的选项是：
All other options are incorrect
1
2
3
1,2
1,3
2,3
1,2,3
其他选项均不正确
1
2
3
1,2
1,3
2,3
1,2,3
From four coordination, it can be deduced that one atom should be square planar coordinated (forming $\mathbf{AB}_4$ edge-sharing connections to produce $\mathbf{AB}_2$), and the other atom should be tetrahedral. The unit cell is shown in the figure: <MultiModal>![The image shows the unit cell of the compound, which is a tetragonal unit cell. The gray spheres represent $A$ atoms with atomic coordinates (0.5,0,0) and (0,0.5,0.5). The yellow spheres represent $B$ atoms with atomic coordinates (0,0,0.25) and (0,0,0.75). In addition, the image also shows parts of $B$ atoms in the unit cells above and below the current unit cell](/media/uploads/3139d914-57d4-42f1-87f5-ffc1685babd2.png)</MultiModal>

From the figure, it is easy to see that the lattice form of the crystal is $tP$.

<Checkpoint>[The crystal lattice form is $tP$](1)</Checkpoint>

There are two orientations of $\mathbf{A}$ atoms around the $\mathbf{B}$ atom.

<Checkpoint>[There are two spatial environments for $\mathbf{B}$ atoms in the crystal](1)</Checkpoint>

The unit cell parameters can be obtained through calculation:

$a=347 \mathrm{pm},c=610 \mathrm{pm}$

Thus, we have the equation:

$\rho=\frac{ZM}{N_AV}=\frac{2M}{N_A*347*347*610*10^{-30}\mathrm{cm^3}}=10.27 \mathrm{g/cm^{3}}$

Solving for $M=227.1\mathrm{g/mol}$, which leads to $\mathrm{PtS}$, $\mathbf{A}$ is $\mathrm{Pt}$, belonging to group VIII. The fourth-period elements in the same group are $\mathrm{Fe,Co,Ni}$. Among them, $\mathrm{Fe}$ exists as native metal in meteorites in nature.

<Checkpoint>[The fourth-period element $\mathrm{Fe}$ in the same group as $\mathbf{A}$ exists as native metal in meteorites in nature](1)</Checkpoint>

Therefore, choose option D
由四配位可以得出，一种原子应为平面四边形配位（形成$\mathbf{AB}_4$共棱连接产生$\mathbf{AB}_2$），另一种原子应为四面体型，晶胞如图所示：<MultiModal>![图片展示了化合物的晶胞，该晶胞为四方晶胞，其中灰色球代表$A$原子，原子坐标为(0.5,0,0)和(0,0.5,0.5)，黄色球代表$B$原子，原子坐标为(0,0,0.25)和(0,0,0.75)，除此之外还展示了该晶胞上下方晶胞的部分$B$原子](/media/uploads/3139d914-57d4-42f1-87f5-ffc1685babd2.png)</MultiModal>

由图易有该晶体点阵形式为$tP$。

<Checkpoint>[该晶体点阵形式为$tP$](1)</Checkpoint>

$\mathbf{B}$原子周围的$\mathbf{A}$原子存在两种取向。

<Checkpoint>[该晶体中$\mathbf{B}$原子存在两种空间环境](1)</Checkpoint>

通过计算可以得到晶胞参数：

$a=347 \mathrm{pm},c=610 \mathrm{pm}$

于是有方程：

$\rho=\frac{ZM}{N_AV}=\frac{2M}{N_A*347*347*610*10^{-30}\mathrm{cm^3}}=10.27 \mathrm{g/cm^{3}}$

解得$M=227.1\mathrm{g/mol}$，从而推出为$\mathrm{PtS}$，$\mathbf{A}$为$\mathrm{Pt}$，属于VIII族，其同族第四周期元素有$\mathrm{Fe,Co,Ni}$，其中$\mathrm{Fe}$在自然界中存在陨铁以单质形式存在。

<Checkpoint>[$\mathbf{A}$的同族第四周期元素$\mathrm{Fe}$在自然界中存在陨铁以单质形式存在](1)</Checkpoint>

因此选择选项D