<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C(OC(C)=O)SC4=CC=CC=C4)O1>CC(C)[Al]([H])C(C)C.ClCCl,$-78\degree \mathrm{C}$>[$\mathbf{A}$], $\mathbf{A}$ is the product](/media/uploads/b16574f7-2f7c-4440-80a1-4c0f2824b047.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C(OC(C)=O)SC4=CC=CC=C4)O1>$\mathrm{K_2CO_3}$,$\mathrm{CH_3OH}$,$25\degree \mathrm{C}$>[$\mathbf{B}$], $\mathbf{B}$ is the product](/media/uploads/1f3b8a44-9314-46ca-93c1-02dabcfc4fd3.png)</MultiModal>

Given that the molecular formulas of reaction products $\mathbf{A}$ and $\mathbf{B}$ are both $\mathrm{C_{20}H_{22}O_4}$, considering stereoisomers, predict the structural formulas of reaction products $\mathbf{A}$ and $\mathbf{B}$ respectively.
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C(OC(C)=O)SC4=CC=CC=C4)O1>CC(C)[Al]([H])C(C)C.ClCCl,$-78\degree \mathrm{C}$>[$\mathbf{A}$],$\mathbf{A}$为产物](/media/uploads/b16574f7-2f7c-4440-80a1-4c0f2824b047.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C(OC(C)=O)SC4=CC=CC=C4)O1>$\mathrm{K_2CO_3}$,$\mathrm{CH_3OH}$,$25\degree \mathrm{C}$>[$\mathbf{B}$],$\mathbf{B}$为产物](/media/uploads/1f3b8a44-9314-46ca-93c1-02dabcfc4fd3.png)</MultiModal>

已知反应产物$\mathbf{A}$和$\mathbf{B}$的分子式均为$\mathrm{C_{20}H_{22}O_4}$，考虑立体异构的条件下，试分别预测反应产物$\mathbf{A}$和$\mathbf{B}$的结构式
All other options are incorrect
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>
其他选项均不正确
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>
<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<MultiModal>![CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>
Based on the molecular formula $\mathrm{C_{20}H_{22}O_4}$ of the reaction products $\mathbf{A}$ and $\mathbf{B}$, it can be inferred that the reaction is apparently the deprotection of the aldehyde group, yielding product $\mathbf{1}$.

<MultiModal>![Product $\mathbf{1}$: CC1(C)OC(COC(C2=CC=CC=C2)C3=CC=CC=C3)C(C=O)O1](/media/uploads/733dc92b-297b-448c-8ae6-12bd9336ce7e.png)</MultiModal>

<Checkpoint>[Product $\mathbf{1}$: CC1(C)OC(COC(C2=CC=CC=C2)C3=CC=CC=C3)C(C=O)O1](1)</Checkpoint>

Next, consider stereoselectivity.

The first reaction is carried out in an aprotic solvent at low temperature, so no isomerization occurs after the protecting group is removed, and product $\mathbf{A}$ with retained configuration is obtained.

<Checkpoint>[The first reaction is carried out in an aprotic solvent at low temperature, so no isomerization occurs after the protecting group is removed, and product $\mathbf{A}$ with retained configuration is obtained](1)</Checkpoint>

<MultiModal>![Product $\mathbf{A}$: CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>

<Checkpoint>[Product $\mathbf{A}$: CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](1)</Checkpoint>

The second reaction is carried out in a protic solvent at room temperature, which facilitates proton transfer reactions. At this time, the epimerization of the aldehyde group at the $\alpha$ position can occur through the enol intermediate $\mathbf{2}$.

<Checkpoint>[The second reaction is carried out in a protic solvent at room temperature, which facilitates proton transfer reactions. At this time, the epimerization of the aldehyde group at the $\alpha$ position can occur through the enol intermediate $\mathbf{2}$](1)</Checkpoint>

<MultiModal>![Enol intermediate $\mathbf{2}$: CC(O/1)(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)C1=C\O](/media/uploads/287dfbb9-96ac-48ee-a3b3-3a6e6b6e3b0f.png)</MultiModal>

<Checkpoint>[Enol intermediate $\mathbf{2}$: CC(O/1)(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)C1=C\O](1)</Checkpoint>

Subsequently, the thermodynamically stable product $\mathbf{B}$ with a greater distance between the aldehyde group and $\mathrm{-CH_2OCHPh_2}$ is obtained.

<Checkpoint>[The thermodynamically stable product $\mathbf{B}$ with a greater distance between the aldehyde group and $\mathrm{-CH_2OCHPh_2}$ is obtained](1)</Checkpoint>

<MultiModal>![Product $\mathbf{B}$: CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<Checkpoint>[Product $\mathbf{B}$: CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](1)</Checkpoint>
根据反应产物$\mathbf{A}$和$\mathbf{B}$的分子式$\mathrm{C_{20}H_{22}O_4}$可以推断出，该反应表观上都是给醛基脱保护，得到产物$\mathbf{1}$

<MultiModal>![产物$\mathbf{1}$：CC1(C)OC(COC(C2=CC=CC=C2)C3=CC=CC=C3)C(C=O)O1](/media/uploads/733dc92b-297b-448c-8ae6-12bd9336ce7e.png)</MultiModal>

<Checkpoint>[产物$\mathbf{1}$：CC1(C)OC(COC(C2=CC=CC=C2)C3=CC=CC=C3)C(C=O)O1](1)</Checkpoint>

接下来考虑立体选择性

第一个反应在低温下的非质子溶剂中进行，因此脱去保护基后不会发生异构化，得到构型保持的产物$\mathbf{A}$

<Checkpoint>[第一个反应在低温下的非质子溶剂中进行，因此脱去保护基后不会发生异构化，得到构型保持的产物$\mathbf{A}$](1)</Checkpoint>

<MultiModal>![产物$\mathbf{A}$：CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](/media/uploads/eea697f7-8a87-4c01-8eba-a2368a5b2019.png)</MultiModal>

<Checkpoint>[产物$\mathbf{A}$：CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@@H](C=O)O1](1)</Checkpoint>

而第二个反应在室温下的质子溶剂中进行，质子转移反应利于发生，此时可通过烯醇中间体$\mathbf{2}$发生醛基$\alpha$位的差向异构化

<Checkpoint>[而第二个反应在室温下的质子溶剂中进行，质子转移反应利于发生，此时可通过烯醇中间体$\mathbf{2}$发生醛基$\alpha$位的差向异构化](1)</Checkpoint>

<MultiModal>![烯醇中间体$\mathbf{2}$：CC(O/1)(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)C1=C\O](/media/uploads/287dfbb9-96ac-48ee-a3b3-3a6e6b6e3b0f.png)</MultiModal>

<Checkpoint>[烯醇中间体$\mathbf{2}$：CC(O/1)(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)C1=C\O](1)</Checkpoint>

随后得到醛基和$\mathrm{-CH_2OCHPh_2}$距离更远的热力学稳定产物$\mathbf{B}$

<Checkpoint>[得到醛基和$\mathrm{-CH_2OCHPh_2}$距离更远的热力学稳定产物$\mathbf{B}$](1)</Checkpoint>

<MultiModal>![产物$\mathbf{B}$：CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](/media/uploads/7c1854d5-e3bd-4a9e-921f-450d87b18e12.png)</MultiModal>

<Checkpoint>[产物$\mathbf{B}$：CC1(C)O[C@@H](COC(C2=CC=CC=C2)C3=CC=CC=C3)[C@H](C=O)O1](1)</Checkpoint>