A compound with a garnet crystal structure contains 4 elements, with mass fractions of $\mathbf{A}~18.55\%, \mathbf{B}~14.52\%, \mathbf{C}~5.60\%, \mathbf{D}~61.33\%$, without considering non-stoichiometric compounds. The following descriptions exist:
1.  The sum of the outermost electron numbers of $\bf A, B, C, D$ is 12.
2.  There are 12 $\bf A$ atoms in a proper unit cell.
3.  There are 16 $\bf A$ atoms in a proper unit cell.
4.  There are 24 $\bf C$ atoms in a proper unit cell.
5.  There are 96 $\bf B$ atoms in a proper unit cell.
6.  According to Pauling's second rule, the charge number of the anion is equal to the sum of the surrounding ionic bond strengths.
7.  There are transition elements among the four elements.
8.  The sum of the outermost electron numbers of $\bf A, D$ is less than 8.
9.  The coordination polyhedra of $\bf A, B, C, D$ in the unit cell do not have regular polyhedra.
10. The molecular weight of this compound is greater than 400.

Which of the following options describes a combination that does not contain incorrect descriptions?
一种具有石榴石型晶体结构的化合物包含4种元素，质量分数分别为$\mathbf{A}~18.55\%, \mathbf{B}~14.52\%, \mathbf{C}~5.60\%, \mathbf{D}~61.33\%$, 不考虑非整比化合物. 有以下描述:
1. $\bf A, B, C,D$的最外层电子数之和为12
2. 一个正当晶胞中有12个$\bf A$原子
3. 一个正当晶胞中有16个$\bf A$原子
4. 一个正当晶胞中有24个$\bf C$原子
5. 一个正当晶胞中有96个$\bf B$原子
6. 根据鲍林第二规则计算, 阴离子的电荷数等于周围的离子键强度之和
7. 四种元素中有副族元素
8. $\bf A,D$的最外层电子数之和小于8
9. 晶胞中$\bf A,B,C,D$的配位多面体没有正多面体
10. 此化合物的分子量大于400

以下选项中描述组合不包含错误描述的是
All other options contain incorrect choices.
2 5 7 9
3 4 6 8
1 4 6 9
1 2 7 9
1 4 6 8
1 4 7 8 9
1 4 5 9 10
1 4 6 9 10
其他选项均包含错误选项
2 5 7 9
3 4 6 8
1 4 6 9
1 2 7 9
1 4 6 8
1 4 7 8 9
1 4 5 9 10
1 4 6 9 10
The general chemical formula of garnet is $\rm X_3Y_2Z_3M_{12}$, where $\rm X, Y, Z$ are cations, and $\rm M$ is an anion. This general formula precisely contains 4 elements, and the ratio of their number of atoms (mole ratio) is fixed at 3 : 2 : 3 : 12.

<Checkpoint>[The ratio of the number of atoms of the 4 elements is 3 : 2 : 3 : 12](1)</Checkpoint>

Determining the types of elements is a key step in solving the problem. Usually, we can assume that the element with the highest mass fraction is oxygen. However, if this assumption cannot lead to a reasonable chemical formula, other possibilities should be considered, such as fluorine, because the molar mass of fluorine is close to that of oxygen and it is also common in minerals. Verification shows that oxygen does not meet the conditions, so fluorine is most likely.

<Checkpoint>[The anion is most likely fluorine](1)</Checkpoint>

Trying when $\mathbf{D}=\mathrm{F}$, the calculations show that $\bf A, B, C$ all have reasonable atomic weights. $\mathbf{D}=\mathrm{F}$, $\mathbf{A}=\mathrm{Na}$, $\mathbf{B}=\mathrm{Al}$, $\mathbf{C}=\mathrm{Li}$, it can be judged that description 7 is incorrect.

<Checkpoint>[$\mathbf{A}=\mathrm{Na}$,$\mathbf{B}=\mathrm{Al}$,$\mathbf{C}=\mathrm{Li}$,$\mathbf{D}=\mathrm{F}$, description 7 is incorrect](2)</Checkpoint>

Relative molecular mass $M(\rm Na_3Al_2Li_3F_{12}) = 371.75$, description 10 is incorrect.

<Checkpoint>[Molecular weight $M = 371.75<400$, description 10 is incorrect](1)</Checkpoint>

The sum of the number of outermost electrons is $1+3+1+7=12$, description 1 is correct. The sum of the number of outermost electrons of $\rm Na, F$ is 8, description 8 is incorrect.

<Checkpoint>[The sum of the number of outermost electrons of $\bf A,B,C,D$ is 12, description 1 is correct, the sum of $\bf A,D$ is 8, description 8 is incorrect](1)</Checkpoint>

In the garnet structure, $Z=8$, so descriptions 2, 3, and 5 are incorrect, and description 4 is correct.

<Checkpoint>[One proper unit cell contains 24 $\bf A$, 24 $\bf C$, descriptions 2, 3, and 5 are incorrect, and description 4 is correct](1)</Checkpoint>

In the garnet structure, all coordination polyhedra include $\rm [NaF_8], [AlF_6],[LiF_4],[FNa_2AlLi]$. According to Pauling's second rule, $\frac{1}{8} \times 2+\frac{3}{6}+\frac{1}{4}=1$, description 6 is correct.

<Checkpoint>[According to Pauling's second rule, $\frac{1}{8} \times 2+\frac{3}{6}+\frac{1}{4}=1$, description 6 is correct](1)</Checkpoint>

In the unit cell, the symmetry of all atomic positions (16a, 24c, 24d, 96h) does not meet the requirements of a regular polyhedron (the highest 16a has only one $\bar{3}$ axis). Due to the different environments, there must be distortion, description 9 is correct.

<Checkpoint>[The symmetry of the atomic positions is lower than the symmetry of a regular polyhedron, there must be distortion, description 9 is correct](1.5)</Checkpoint>

1 4 6 9 are correct, choose D
石榴石的通用化学式为$\rm X_3Y_2Z_3M_{12}$，其中$\rm X,Y,Z$为阳离子，$\rm M$为阴离子。这个通式正好包含4种元素，其原子个数比（摩尔比）是固定的 3 : 2 : 3 : 12。

<Checkpoint>[4种元素的原子个数比是3 : 2 : 3 : 12](1)</Checkpoint>

确定元素种类 这是求解问题的关键步骤。通常，我们可以假设质量分数最高的元素是氧。但如果该假设无法推导出合理的化学式，则应考虑其他可能性，例如氟，因为氟的摩尔质量与氧相近，且在矿物中也常见。验证得到氧不符合条件, 因此最可能是氟.

<Checkpoint>[阴离子最可能是氟](1)</Checkpoint>

尝试当$\mathbf{D}=\mathrm{F}$时, 计算得到$\bf A,B,C$都有合理的原子量. $\mathbf{D}=\mathrm{F}$, $\mathbf{A}=\mathrm{Na}$, $\mathbf{B}=\mathrm{Al}$, $\mathbf{C}=\mathrm{Li}$, 可以判断描述7错误. 

<Checkpoint>[$\mathbf{A}=\mathrm{Na}$,$\mathbf{B}=\mathrm{Al}$,$\mathbf{C}=\mathrm{Li}$,$\mathbf{D}=\mathrm{F}$, 描述7错误](2)</Checkpoint>

相对分子质量 $M(\rm Na_3Al_2Li_3F_{12}) = 371.75$, 描述10错误.

<Checkpoint>[分子量 $M = 371.75<400$描述10错误](1)</Checkpoint>

最外层电子数之和为$1+3+1+7=12$, 描述1正确. $\rm Na, F$最外层电子书之和为8, 描述8错误. 

<Checkpoint>[$\bf A,B,C,D$ 最外层电子数之和为12,描述1正确, $\bf A,D$之和为8, 描述8错误](1)</Checkpoint>

石榴石结构中$Z=8$, 因此描述2,3,5错误,描述4正确. 

<Checkpoint>[一个正当晶胞含有24个$\bf A$, 24个$\bf C$, 描述2,3,5错误,描述4正确](1)</Checkpoint>

石榴石结构中, 所有的配位多面体包括$\rm [NaF_8], [AlF_6],[LiF_4],[FNa_2AlLi]$, 根据鲍林第二规则计算$\frac{1}{8} \times 2+\frac{3}{6}+\frac{1}{4}=1$, 描述6正确. 

<Checkpoint>[根据鲍林第二规则计算$\frac{1}{8} \times 2+\frac{3}{6}+\frac{1}{4}=1$, 描述6正确](1)</Checkpoint>

晶胞中, 所有原子所在位置(16a, 24c, 24d, 96h)的对称性达不到正多面体的要求(最高的16a仅一条$\bar{3}$轴), 由于所处环境不同, 必然存在畸变, 描述9正确. 

<Checkpoint>[原子所在位置的对称性低于正多面体的对称性, 必然存在畸变, 描述9正确](1.5)</Checkpoint>

1 4 6 9 正确, 选D