The reaction of metallic potassium with carbon monoxide can produce a black powder with the chemical composition $\rm KCO$.

It is known that the powder composition includes two substances, $\bf A$ and $\bf B$. $\bf A$ reacts with dilute hydrochloric acid to produce a monocarboxylic acid. $\bf B$ reacts with dilute hydrochloric acid to produce a substance $\bf D$ containing only one type of functional group, a hydroxyl group. $\bf D$ is oxidized by chlorine gas in aqueous solution to produce a substance $\bf E$ with 2 waters of crystallization. $\bf E$ produces $\bf F$ under high vacuum heating, where all atoms have the same chemical environment and are extremely unstable.

Which of the following statements is correct?
金属钾与一氧化碳反应可制取一种黑色粉末，其化学组成为$\rm KCO$。

已知其粉末组成包含$\bf A, B$两种物质，$\bf A$遇到稀盐酸生成一种一元羧酸；$\bf B$遇到稀盐酸生成一种只含有羟基一种官能团的物质$\bf D$。$\bf D$在水溶液中被氯气氧化生成带2个结晶水的物质$\bf E$，$\bf E$在高度真空加热下产生$\bf F$，其所有原子化学环境均相同且极其不稳定。

下列说法正确的是：
All other options are incorrect
$\bf A$ only has a two-fold rotation axis
The anion of $\bf B$ does not possess strong reducing properties.
$\bf D, E, F$ are all ternary compounds
Chemical equation for the synthesis of $\bf E$, when the coefficients are balanced to the simplest integer ratio, the sum of the reactant coefficients and the sum of the product coefficients have a prime number.
其他选项均不正确
$\bf A$的阴离子只具有二重旋转轴
$\bf B$的阴离子不具有强还原性
$\bf D, E，F$均为三元化合物
合成$\bf E$的化学方程式，系数配平为最简整数比时，反应物系数和和产物系数和有一个质数
The anions of $\bf A, B$ obviously have the simplest chemical formula $\rm CO^-$. Since $\bf A$ reacts with acid to produce a monocarboxylic acid, the anion of $\bf A$ can only be $\rm C_2O_2^{2-}$, with the structure [O-]C#C[O-], which hydrolyzes to produce $\rm HOCH_2COOH$. $\rm C_2O_2^{2-}$ has a $\rm C_\infty$ axis, so option B is incorrect.

<Checkpoint>[The anion of $\bf A$ can only be $\rm C_2O_2^{2-}$, with the structure [O-]C#C[O-]](1)</Checkpoint>

<Checkpoint>[$\rm C_2O_2^{2-}$ has a $\rm C_\infty$ axis](1)</Checkpoint>

$\bf D$, produced by the reaction of $\bf B$ with acid, has only one type of functional group, the hydroxyl group, which is obviously hexahydroxybenzene, with the structure OC1=C(O)C(O)=C(O)C(O)=C1O, and the chemical formula $\rm C_6(OH)_6$. Therefore, the structure of the anion of $\bf B$ is [O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-], which has strong reducing properties, so option C is incorrect.

<Checkpoint>[The structure of $\bf D$ is OC1=C(O)C(O)=C(O)C(O)=C1O](1)</Checkpoint>

<Checkpoint>[The structure of the anion of $\bf B$ is [O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-]](1)</Checkpoint>

<Checkpoint>[The anion of $\bf B$ has strong reducing properties](1)</Checkpoint>

$\bf D$ is oxidized in aqueous solution, and should produce cyclohexanhexone, but it is extremely unstable. The carbonyl groups are extremely electron-deficient and are easily attacked by water nucleophilically to form carbonyl hydrates. Therefore, the chemical formula of $\bf E$ is $\rm C_6(OH)_{12}\cdot 2H_2O$, then obviously $\bf F$ is cyclohexanhexone, with the structure O=C(C(C(C(C1=O)=O)=O)=O)C1=O.

<Checkpoint>[The chemical formula of $\bf E$ is $\rm C_6(OH)_{12}\cdot 2H_2O$](1)</Checkpoint>

<Checkpoint>[$\bf F$ is cyclohexanhexone, with the structure O=C(C(C(C(C1=O)=O)=O)=O)C1=O](1)</Checkpoint>

The chemical equation for the formation of $\bf E$ is:

$\rm C_6(OH)_6 + 3Cl_2 + 8H_2O = C_6(OH)_{12}\cdot 2H_2O + 6HCl$

<Checkpoint>[$\rm C_6(OH)_6 + 3Cl_2 + 8H_2O = C_6(OH)_{12}\cdot 2H_2O + 6HCl$](1)</Checkpoint>

According to the chemical formulas and equation, option E is correct, and D is incorrect.

<MultiModal>![The structure of the anion of $\bf A$ is [O-]C#C[O-]; the structure of $\bf D$ is OC1=C(O)C(O)=C(O)C(O)=C1O; the structure of $\bf F$ is O=C(C(C(C(C1=O)=O)=O)=O)C1=O; the structure of the anion of $\bf B$ is [O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-]](/media/uploads/5d20bd13-7ce8-497d-895a-7028570c12eb.png)</MultiModal>
$\bf A,B$的阴离子很明显最简化学式为$\rm CO^-$。由于$\bf A$与酸反应产生一元羧酸，因此$\bf A$阴离子只能为$\rm C_2O_2^{2-}$,结构为[O-]C#C[O-]，水解产生$\rm HOCH_2COOH$。$\rm C_2O_2^{2-}$具有$\rm C_\infty$轴，选项B错误。

<Checkpoint>[$\bf A$阴离子只能为$\rm C_2O_2^{2-}$,结构为[O-]C#C[O-]](1)</Checkpoint>

<Checkpoint>[$\rm C_2O_2^{2-}$具有$\rm C_\infty$轴](1)</Checkpoint>

$\bf B$与酸反应产生的$\bf D$只有羟基一种官能团，很明显为苯六酚，结构为OC1=C(O)C(O)=C(O)C(O)=C1O，化学式为$\rm C_6(OH)_6$。因此$\bf B$阴离子结构为[O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-]，具有强还原性，选项C错误。

<Checkpoint>[$\bf D$结构为OC1=C(O)C(O)=C(O)C(O)=C1O](1)</Checkpoint>

<Checkpoint>[$\bf B$阴离子结构为[O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-]](1)</Checkpoint>

<Checkpoint>[$\bf B$阴离子具有强还原性](1)</Checkpoint>

$\bf D$在水溶液中被氧化，本应生成环己六酮，但其极不稳定，羰基极其缺电子，容易被水亲核进攻生成羰基水合物，因此$\bf E$化学式为$\rm C_6(OH)_{12}\cdot 2H_2O$，则明显$\bf F$为环己六酮，结构为O=C(C(C(C(C1=O)=O)=O)=O)C1=O。

<Checkpoint>[$\bf E$化学式为$\rm C_6(OH)_{12}\cdot 2H_2O$](1)</Checkpoint>

<Checkpoint>[$\bf F$为环己六酮，结构为O=C(C(C(C(C1=O)=O)=O)=O)C1=O](1)</Checkpoint>

$\bf E$生成的化学方程式为：

$\rm C_6(OH)_6 + 3Cl_2 + 8H_2O = C_6(OH)_{12}\cdot 2H_2O + 6HCl$

<Checkpoint>[$\rm C_6(OH)_6 + 3Cl_2 + 8H_2O = C_6(OH)_{12}\cdot 2H_2O + 6HCl$](1)</Checkpoint>

根据化学式和方程式，选项E正确，D错误。

<MultiModal>![$\bf A$阴离子结构为[O-]C#C[O-]；$\bf D$结构为OC1=C(O)C(O)=C(O)C(O)=C1O；$\bf F$结构为O=C(C(C(C(C1=O)=O)=O)=O)C1=O；$\bf B$阴离子结构为[O-]C1=C([O-])C([O-])=C([O-])C([O-])=C1[O-]](/media/uploads/5d20bd13-7ce8-497d-895a-7028570c12eb.png)</MultiModal>