The following reactions are known:

<MultiModal>![CC1=C(C(Cl)=O)C=C(C)C2=CC=CC=C21 undergoes a reversible reaction with $\mathrm{O_2}$ under the conditions of methylene blue and light, yielding compound $\mathbf{A}$. Subsequently, $\mathbf{A}$ first reacts with $\mathrm{NaH}$, then with $\mathbf{M}$ to form $\mathbf{B}$. Finally, $\mathbf{B}$ generates $\mathbf{C}$ under heating conditions.](/media/uploads/9f0a1cba-e901-4b0f-b688-16795b333ac7.png)</MultiModal>

Here, $\mathbf{B}$ and $\mathbf{C}$ are isomers. Regarding this reaction, the following experimental facts are observed:

(1) When $\mathbf{M}$ is replaced with $\mathbf{N}$ while keeping other conditions unchanged, the corresponding compound analogous to $\mathbf{B}$ can still be obtained with a high yield. However, in the final step of the reaction, a large amount of oxygen is released, and almost no compound corresponding to $\mathbf{C}$ is produced.

(2) During the transformation from $\mathbf{B}$ to $\mathbf{C}$, if $\mathbf{P}$ is added, the oxidation product $\mathbf{Q}$ of $\mathbf{P}$ can be detected, and the yield of $\mathbf{C}$ is almost the same as when $\mathbf{P}$ is not added.

<MultiModal>![$\mathbf{M}$ is O=C(C1=CC=CC=C1C2)C3=C2C=CC=C3; $\mathbf{N}$ is OC(C=C1)=CC=C1C2=C3C(C=CC=C3)=CC4=CC=CC=C42; $\mathbf{P}$ is CC(OC1=C2C=CC=CC2=CC3=C1C=CC=C3)=O](/media/uploads/89042561-bb8c-4528-9859-503cdebecf18.png)</MultiModal>

Which of the following statements is incorrect? (If all are correct, select F.)
已知下列反应：

<MultiModal>![CC1=C(C(Cl)=O)C=C(C)C2=CC=CC=C21在亚甲基蓝，光照的条件下，和$\mathrm{O_2}$发生可逆反应，生成物质$\mathbf{A}$。随后，$\mathbf{A}先和$\mathrm{NaH}$反应，后和$\mathbf{M}$反应形成$\mathbf{B}$。最后，$\mathbf{B}$在加热的条件下生成$\mathbf{C}$](/media/uploads/9f0a1cba-e901-4b0f-b688-16795b333ac7.png)</MultiModal>

其中$\mathbf{B}$和$\mathbf{C}$互为同分异构体。关于此反应，有下列实验事实：

（1）将$\mathbf{M}$换成$\mathbf{N}$，其他条件不变，同样能以较高产率得到相应于$\mathbf{B}$的化合物，但在最后一步反应中放出大量氧气，且几乎没有相应于$\mathbf{C}$的化合物产生；

（2）在$\mathbf{B}$到$\mathbf{C}$的转化过程中加入$\mathbf{P}$，可检测到$\mathbf{P}$的氧化产物$\mathbf{Q}$，且$\mathbf{C}$的产率和不加入$\mathbf{P}$时几乎相同。

<MultiModal>![$\mathbf{M}$为O=C(C1=CC=CC=C1C2)C3=C2C=CC=C3；$\mathbf{N}$为OC(C=C1)=CC=C1C2=C3C(C=CC=C3)=CC4=CC=CC=C42;$\mathbf{P}$为CC(OC1=C2C=CC=CC2=CC3=C1C=CC=C3)=O](/media/uploads/89042561-bb8c-4528-9859-503cdebecf18.png)</MultiModal>

下列说法中错误的是(若均正确，选F)
The number of chiral carbons in $\mathbf{A}$ is 2.
There are $\mathrm{H}$ atoms in $\mathbf{B}$ existing in $12$ different chemical environments.
There are $11$ types of hydrogen chemical environments in $\mathbf{C}$.
$\mathbf{B}\rightarrow\mathbf{C}$ is dominated by intramolecular reactions
After replacing $\mathbf{M}$ with $\mathbf{N}$, no corresponding $\mathbf{C}$ is generated because the spatial distance is too far to achieve oxygen transfer.
All of the above options are correct
$\mathbf{A}$中手性碳个数为2
$\mathbf{B}$中有存在$12$种化学环境的$\mathrm{H}$
$\mathbf{C}$中有存在$11$种化学环境的$\mathrm{H}$
$\mathbf{B}\rightarrow\mathbf{C}$以分子内反应为主
$\mathbf{M}$换成$\mathbf{N}$后没有相应$\mathbf{C}$生成是由于空间距离过远无法实现氧气转移
以上选项都正确
First, the reaction process is inferred. Since the question states, "but a large amount of oxygen is released in the final step of the reaction," the first step must involve an addition reaction with $\mathrm{O_2}$, forming CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(Cl)=O, with 2 chiral carbons, making option A correct.  

<Checkpoint>[The structure of $\mathbf{A}$ is CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(Cl)=O](1)</Checkpoint>  

Since $\mathbf{M}$ is essentially anthranol, $\mathrm{NaH}$ will react with the phenolic hydroxyl group, turning $\mathbf{M}$ into a nucleophile. Subsequently, it reacts with $\mathbf{A}$ to form CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(OC4=C5C=CC=CC5=CC6=C4C=CC=C6)=O, meaning $\mathbf{B}$ has 12 chemically distinct hydrogens, making option B correct.  

<Checkpoint>[The structure of $\mathbf{B}$ is CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(OC4=C5C=CC=CC5=CC6=C4C=CC=C6)=O](1)</Checkpoint>  

Since the question hints that "$\mathbf{B}$ and $\mathbf{C}$ are isomers," and $\mathbf{B}\rightarrow\mathbf{C}$ is a heating process, the transformation yields the thermodynamic product. Structures with more complete benzene rings are more stable, so $\mathbf{B}\rightarrow\mathbf{C}$ converts two complete benzene rings into three, meaning $\mathbf{C}$ is CC1=CC(=C(C)C2=C1C=CC=C2)C(=O)OC34C5=C(C=CC=C5)C(C6=C3C=CC=C6)OO4, and $\mathbf{C}$ has 12 chemically distinct hydrogens, making option C incorrect.  

<Checkpoint>[The structure of $\mathbf{C}$ is CC1=CC(=C(C)C2=C1C=CC=C2)C(=O)OC34C5=C(C=CC=C5)C(C6=C3C=CC=C6)OO4](1)</Checkpoint>  

According to the question, "when $\mathbf{M}$ is replaced with $\mathbf{N}$, under otherwise identical conditions, the compound corresponding to $\mathbf{B}$ is obtained in high yield, but a large amount of oxygen is released in the final step of the reaction, and almost no compound corresponding to $\mathbf{C}$ is produced." The key difference between $\mathbf{M}$ and $\mathbf{N}$ lies in the fact that, in the corresponding product, the anthracene moiety in the $\mathbf{N}$-derived structure is farther from the peroxide bond. Thus, the inability to rearrange and the release of oxygen instead indicate that $\mathbf{B}\rightarrow\mathbf{C}$ is an intramolecular reaction and is sterically controlled, making options D and E correct.  

<Checkpoint>[$\mathbf{B}\rightarrow\mathbf{C}$ is an intramolecular reaction](1)</Checkpoint>  

In conclusion, the answer is C.
首先对反应过程进行推断。由于题干指出，“但在最后一步反应中放出大量氧气”，第一步一定是和$\mathrm{O_2}$发生加和反应，即形成CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(Cl)=O，手性碳个数为2，选项A正确。

<Checkpoint>[$\mathbf{A}$的结构为CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(Cl)=O](1)</Checkpoint>

由于$\mathbf{M}$实质为蒽酚，所以$\mathrm{NaH}$会和酚羟基反应，使$\mathbf{M}$成为一个亲核基团。随后，它和$\mathbf{A}$反应，形成CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(OC4=C5C=CC=CC5=CC6=C4C=CC=C6)=O，即$\mathbf{B}$中有12种化学环境的氢，选项B正确。

<Checkpoint>[$\mathbf{B}$的结构为CC12C=C(C(C3=C1C=CC=C3)(OO2)C)C(OC4=C5C=CC=CC5=CC6=C4C=CC=C6)=O](1)</Checkpoint>

由于题干提示“$\mathbf{B}$和$\mathbf{C}$互为同分异构体”，$\mathbf{B}\rightarrow\mathbf{C}$是加热过程，因此发生的是向热力学产物的转化。由于有更多完整苯环的结构会更稳定，$\mathbf{B}\rightarrow\mathbf{C}$会两个完整的苯环转化为三个完整的苯环，即$\mathbf{C}$为CC1=CC(=C(C)C2=C1C=CC=C2)C(=O)OC34C5=C(C=CC=C5)C(C6=C3C=CC=C6)OO4，即$\mathbf{C}$中有12种化学环境的氢，选项C错误。

<Checkpoint>[$\mathbf{C}$的结构为CC1=CC(=C(C)C2=C1C=CC=C2)C(=O)OC34C5=C(C=CC=C5)C(C6=C3C=CC=C6)OO4](1)</Checkpoint>

由于题目描述，“将$\mathbf{M}$换成$\mathbf{N}$，其他条件不变，同样能以较高产率得到相应于$\mathbf{B}$的化合物，但在最后一步反应中放出大量氧气，且几乎没有相应于$\mathbf{C}$的化合物产生”，可以发现$\mathbf{M}$和$\mathbf{N}$的差别主要体现在：对应产物中，$\mathbf{N}$对应结构的蒽距离过氧键距离更远。因此，不能重排而只能放出氧气说明$\mathbf{B}\rightarrow\mathbf{C}$是分子内反应，且反应受空间位阻控制，选项D和E正确。

<Checkpoint>[$\mathbf{B}\rightarrow\mathbf{C}$是分子内反应](1)</Checkpoint>

综上，选C。