$\bf{S}$ crystal contains three types of ions: tetrahedral $\bf{A}$, $\bf{B}$, and heavy atom coordination polyhedron octahedral $\bf{C}$, in a ratio of $1:1:1$. It belongs to the orthorhombic crystal system, with cell parameters $a=6.9550 Å，b=6.1420 Å，c=11.2180 Å$. There are two chemical formulas in one unit cell. Heating $\bf{S}$ to 100℃ results in a weight loss of 44.05%, and further heating results in another weight loss of 10.61%, yielding a stable compound $\bf{X}$. $\bf{X}$ contains 27.83% of the non-metallic element $\bf{Y}$. Which of the following statements are correct:

1.  All elements in $\bf{S}$ are macroelements in plants.
2. The sum of all atoms in the chemical formula of $\bf{X}$ is 12.
3. From the transformation of $\bf{S}$ to $\bf{X}$, 14 moles of gas are produced for every 1 mole of $\bf{X}$ formed.
4. The density of the crystal is $\mathrm{1.701 g/cm^3}$.
5. The stoichiometric ratio of each species in the second step heating chemical equation is 2:1:2:1.
$\bf{S}$晶体中含有三种离子：四面体的$\bf{A}$、$\bf{B}$和重原子配位多面体为八面体的$\bf{C}$，其比例为$1:1:1$。其属于正交晶系，晶胞参数为$a=6.9550 Å，b=6.1420 Å，c=11.2180 Å$。在一个晶胞中含有两个化学式。将$\bf{S}$加热至100℃，会失重44.05%，进一步加热会再失重10.61%，得到稳定化合物$\bf{X}$。$\bf{X}$中含非金属元素$\bf{Y}$ 27.83%。下面说法中正确的有：

1.  $\bf{S}$中的所有元素都是植物中的常量元素
2. $\bf{X}$的化学式中所有原子数之和为12
3. 从$\bf{S}$转化为$\bf{X}$，每生成1摩尔$\bf{X}$，会产生14 摩尔气体
4. 该晶体的密度为$\mathrm{1.701 g/cm^3}$
5. 第二步加热化学方程式中各个物种的化学计量比为2：1：2：1
All other options are incorrect
1.5.
1.2.4.
2.4.5.
3.4.
2.5.
1.4.5.
2.3.5.
其他选项均不正确
1.5.
1.2.4.
2.4.5.
3.4.
2.5.
1.4.5.
2.3.5.
Based on the weight loss from water release, the octahedral $\bf{C}$ should be $\mathrm{\mathbf{M}(H_2O)_6^{n+}}$

$(18.016\times6)/0.4405\times(1-0.4405-0.1061)\times0.2783=30.97g/mol $

Therefore, $\bf{Y}$ is element $P$

<Checkpoint>[Therefore, $\bf{Y}$ is element $P$](1)</Checkpoint>

Considering that the tetrahedral anion should be $\mathrm{PO_4^{3-}}$, the other tetrahedral cation is most likely $\mathrm{NH_4^+}$ (because there is no residual weight after heating)

<Checkpoint>[Tetrahedral anion should be $\mathrm{PO_4^{3-}}$](1)</Checkpoint>

<Checkpoint>[Tetrahedral cation is most likely $\mathrm{NH_4^+}$](1)</Checkpoint>

From the remaining mass, the metal ion is $\mathrm{Mg(H_2O)_6^{2+}}$

1 is correct.

<Checkpoint>[Metal ion is $\mathrm{Mg(H_2O)_6^{2+}}$](1)</Checkpoint>

$\bf{X}$ should be pyrophosphate. Based on the mass fraction, it can be deduced that $\bf{X}$ is $\mathrm{Mg_2P_2O_7}$, 2 is incorrect.

<Checkpoint>[$\bf{X}$ is $\mathrm{Mg_2P_2O_7}$](1)</Checkpoint>

The chemical equations involved in the decomposition:

$\mathrm{NH_4Mg(H_2O)_6PO_4==NH_4MgPO_4+6H_2O}$

$\mathrm{2NH_4MgPO_4==Mg_2P_2O_7+2NH_3+H_2O}$

<Checkpoint>[$\mathrm{NH_4Mg(H_2O)_6PO_4==NH_4MgPO_4+6H_2O}$  $\mathrm{2NH_4MgPO_4==Mg_2P_2O_7+2NH_3+H_2O}$](1)</Checkpoint>

5 is correct

From $\bf{S}$ to $\bf{X}$, for every 1 mole of $\bf{X}$ generated, 15 moles of gas will be produced, 3 is incorrect.

$ρ=ZM/N_AV=(2*245.4)/(Na*6.955*6.142*11.218*10^{-24} )=1.701g/cm^3$

<Checkpoint>[$ρ=ZM/N_AV=(2*245.4)/(N_A*6.955*6.142*11.218*10^{-24} )=1.701g/cm^3$](1)</Checkpoint>

4. is correct

Therefore, G is correct.
根据失重放出水可以知道，八面体的$\bf{C}$应为$\mathrm{\mathbf{M}(H_2O)_6^{n+}}$

$(18.016\times6)/0.4405\times(1-0.4405-0.1061)\times0.2783=30.97g/mol $

故$\bf{Y}$为$P$元素

<Checkpoint>[故$\bf{Y}$为$P$元素](1)</Checkpoint>

联想到四面体阴离子应为$\mathrm{PO_4^{3-}}$，另一个四面体阳离子极可能为$\mathrm{NH_4^+}$(因为加热后无余重)

<Checkpoint>[四面体阴离子应为$\mathrm{PO_4^{3-}}$](1)</Checkpoint>

<Checkpoint>[四面体阳离子极可能为$\mathrm{NH_4^+}$](1)</Checkpoint>

余下质量可得，金属离子为$\mathrm{Mg(H_2O)_6^{2+}}$

1正确。

<Checkpoint>[金属离子为$\mathrm{Mg(H_2O)_6^{2+}}$](1)</Checkpoint>

$\bf{X}$应为焦磷酸盐，由质量分数可以推出$\bf{X}$为$\mathrm{Mg_2P_2O_7}$， 2错误。

<Checkpoint>[$\bf{X}$为$\mathrm{Mg_2P_2O_7}$](1)</Checkpoint>

分解涉及的化学方程式：

$\mathrm{NH_4Mg(H_2O)_6PO_4==NH_4MgPO_4+6H_2O}$

$\mathrm{2NH_4MgPO_4==Mg_2P_2O_7+2NH_3+H_2O}$

<Checkpoint>[$\mathrm{NH_4Mg(H_2O)_6PO_4==NH_4MgPO_4+6H_2O}$  $\mathrm{2NH_4MgPO_4==Mg_2P_2O_7+2NH_3+H_2O}$](1)</Checkpoint>

5正确

从$\bf{S}$转化为$\bf{X}$，每生成1摩尔$\bf{X}$，会产生15 摩尔气体，3错误。

$ρ=ZM/N_AV=(2*245.4)/(Na*6.955*6.142*11.218*10^{-24} )=1.701g/cm^3$

<Checkpoint>[$ρ=ZM/N_AV=(2*245.4)/(N_A*6.955*6.142*11.218*10^{-24} )=1.701g/cm^3$](1)</Checkpoint>

4.正确

因此G是正确的。